(2n-3)(4n^2-n+5)=

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Solution for (2n-3)(4n^2-n+5)= equation: 


Simplifying
(2n + -3)(4n2 + -1n + 5) = 0

Reorder the terms:
(-3 + 2n)(4n2 + -1n + 5) = 0

Reorder the terms:
(-3 + 2n)(5 + -1n + 4n2) = 0

Multiply (-3 + 2n) * (5 + -1n + 4n2)
(-3(5 + -1n + 4n2) + 2n * (5 + -1n + 4n2)) = 0
((5 * -3 + -1n * -3 + 4n2 * -3) + 2n * (5 + -1n + 4n2)) = 0
((-15 + 3n + -12n2) + 2n * (5 + -1n + 4n2)) = 0
(-15 + 3n + -12n2 + (5 * 2n + -1n * 2n + 4n2 * 2n)) = 0
(-15 + 3n + -12n2 + (10n + -2n2 + 8n3)) = 0

Reorder the terms:
(-15 + 3n + 10n + -12n2 + -2n2 + 8n3) = 0

Combine like terms: 3n + 10n = 13n
(-15 + 13n + -12n2 + -2n2 + 8n3) = 0

Combine like terms: -12n2 + -2n2 = -14n2
(-15 + 13n + -14n2 + 8n3) = 0

Solving
-15 + 13n + -14n2 + 8n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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